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Popular >

extreme f(x)=x^4-32x+3

Solution

extreme points

f (x) = x^{4} - 32 x + 3

Solution

Minimum (2, - 45)

Solution steps

f^{'} (x) = 4 x^{3} - 32

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{4} - 32 x + 3 : - 45

Minimum (2, - 45)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4-32x+3 ?
The extreme f(x)=x^4-32x+3 is Minimum(2,-45)