What is the extreme f(x)=-sqrt(9-x^2) ?

The extreme f(x)=-sqrt(9-x^2) is Maximum(-3,0),Minimum(0,-3),Maximum(3,0)

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extreme f(x)=-sqrt(9-x^2)

extreme points

f (x) = - 9 - x^{2}

Maximum (- 3, 0), Minimum (0, - 3), Maximum (3, 0)

Solution steps

f^{'} (x) = \frac{x}{9 - x ^{2}}

Find intervals:

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3

Plug

x = - 3

into

- 9 - x^{2} : 0

Maximum (- 3, 0)

Plug

x = 0

into

- 9 - x^{2} : - 3

Minimum (0, - 3)

Plug

x = 3

into

- 9 - x^{2} : 0

Maximum (3, 0)

Maximum (- 3, 0), Minimum (0, - 3), Maximum (3, 0)

f (x) = 3 + (x + 2)^{2}

f (x) = 2 x^{2} + x - 5

f (x) = ln (y - x^{2}) + ln (y - 2 x)

f (x) = 10000 + 2500 x - 5 x^{2}

f (x) = 2 x^{2} + y^{3} - 6 x y + 2

What is the extreme f(x)=-sqrt(9-x^2) ?
The extreme f(x)=-sqrt(9-x^2) is Maximum(-3,0),Minimum(0,-3),Maximum(3,0)