What is the extreme f(x)=10000+2500x-5x^2 ?

The extreme f(x)=10000+2500x-5x^2 is Maximum(250,322500)

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extreme f(x)=10000+2500x-5x^2

extreme points

f (x) = 10000 + 2500 x - 5 x^{2}

Maximum (250, 322500)

Solution steps

f^{'} (x) = - 10 x + 2500

Find intervals:

Increasing

: - \infty < x < 250,

Decreasing

: 250 < x < \infty

Plug

x = 250

into

10000 + 2500 x - 5 x^{2} : 322500

Maximum (250, 322500)

f (x) = 2 x^{2} + y^{3} - 6 x y + 2

f (x) = 4 x^{2} + 3

f (x) = (\frac{1}{12} x^{3} - 9 x + 5)

f (x) = 2 x^{2} + 18 x + 16

y = 3 x^{2} = 12 x + 11

What is the extreme f(x)=10000+2500x-5x^2 ?
The extreme f(x)=10000+2500x-5x^2 is Maximum(250,322500)