What is the extreme f(x)=x^3-4x^2-3x-6 ?

The extreme f(x)=x^3-4x^2-3x-6 is Maximum(-1/3 ,-148/27),Minimum(3,-24)

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extreme f(x)=x^3-4x^2-3x-6

extreme points

f (x) = x^{3} - 4 x^{2} - 3 x - 6

Maximum (- \frac{1}{3}, - \frac{148}{27}), Minimum (3, - 24)

Solution steps

f^{'} (x) = 3 x^{2} - 8 x - 3

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - 4 x^{2} - 3 x - 6 : - \frac{148}{27}

Maximum (- \frac{1}{3}, - \frac{148}{27})

Plug

x = 3

into

x^{3} - 4 x^{2} - 3 x - 6 : - 24

Minimum (3, - 24)

Maximum (- \frac{1}{3}, - \frac{148}{27}), Minimum (3, - 24)

f (x) = \frac{5}{x ^{2} + 1}

f (x) - \frac{1}{2} (x + 1)^{2} - \frac{3}{2}

f (x) = x^{3} - 4 x^{2} - 3 x + 1

f (x) = x^{3} - 4 x^{2} - 3 x + 3

f (x) = (x^{2} + 2 y^{2}) e^{1 - x^{2} - y^{2}}

What is the extreme f(x)=x^3-4x^2-3x-6 ?
The extreme f(x)=x^3-4x^2-3x-6 is Maximum(-1/3 ,-148/27),Minimum(3,-24)