What is the extreme f(x)-1/2 (x+1)^2-3/2 ?

The extreme f(x)-1/2 (x+1)^2-3/2 is Saddle(1,0)

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extreme f(x)-1/2 (x+1)^2-3/2

extreme points

f (x) - \frac{1}{2} (x + 1)^{2} - \frac{3}{2}

Saddle (1, 0)

Solution steps

Find the critical points:

(1, 0)

\frac{\partial ^{2} f}{\partial f ^{2}} = - 1

D (f, x) = - 1

Check the sign of at each critical point

Check critical point

(1, 0) :

Saddle

Saddle (1, 0)

f (x) = x^{3} - 4 x^{2} - 3 x + 1

f (x) = x^{3} - 4 x^{2} - 3 x + 3

f (x) = (x^{2} + 2 y^{2}) e^{1 - x^{2} - y^{2}}

f (t) = - 0.01 t^{2} + 4 t

2 x + \frac{2}{3}

What is the extreme f(x)-1/2 (x+1)^2-3/2 ?
The extreme f(x)-1/2 (x+1)^2-3/2 is Saddle(1,0)