What is the extreme f(x)=4x^5+25x^4-40x^3-2 ?

The extreme f(x)=4x^5+25x^4-40x^3-2 is Maximum(-6,9934),Saddle(0,-2),Minimum(1,-13)

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extreme f(x)=4x^5+25x^4-40x^3-2

extreme points

f (x) = 4 x^{5} + 25 x^{4} - 40 x^{3} - 2

Maximum (- 6, 9934), Saddle (0, - 2), Minimum (1, - 13)

Solution steps

f^{'} (x) = 20 x^{4} + 100 x^{3} - 120 x^{2}

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 6

into

4 x^{5} + 25 x^{4} - 40 x^{3} - 2 : 9934

Maximum (- 6, 9934)

Plug

x = 0

into

4 x^{5} + 25 x^{4} - 40 x^{3} - 2 : - 2

Saddle (0, - 2)

Plug

x = 1

into

4 x^{5} + 25 x^{4} - 40 x^{3} - 2 : - 13

Minimum (1, - 13)

Maximum (- 6, 9934), Saddle (0, - 2), Minimum (1, - 13)

f (x) = x^{3} - 2 x^{2} + 1 x

f (x) = (x^{2} - 6 x) (y^{2} - 7 y)

f (x) = - 5 sec (x)

f (x) = (1)^{3 n}

\frac{2 x + 1}{3 x ^{2} - 39 x + 108}

What is the extreme f(x)=4x^5+25x^4-40x^3-2 ?
The extreme f(x)=4x^5+25x^4-40x^3-2 is Maximum(-6,9934),Saddle(0,-2),Minimum(1,-13)