What is the extreme f(x)=x^3-2x^2+1x ?

The extreme f(x)=x^3-2x^2+1x is Maximum(1/3 , 4/27),Minimum(1,0)

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extreme f(x)=x^3-2x^2+1x

extreme points

f (x) = x^{3} - 2 x^{2} + 1 x

Maximum (\frac{1}{3}, \frac{4}{27}), Minimum (1, 0)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x + 1

Find intervals:

Increasing

: - \infty < x < \frac{1}{3},

Decreasing

: \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = \frac{1}{3}

into

x^{3} - 2 x^{2} + 1 x : \frac{4}{27}

Maximum (\frac{1}{3}, \frac{4}{27})

Plug

x = 1

into

x^{3} - 2 x^{2} + 1 x : 0

Minimum (1, 0)

Maximum (\frac{1}{3}, \frac{4}{27}), Minimum (1, 0)

f (x) = (x^{2} - 6 x) (y^{2} - 7 y)

f (x) = - 5 sec (x)

f (x) = (1)^{3 n}

\frac{2 x + 1}{3 x ^{2} - 39 x + 108}

y = 2 x^{2} + 8 x - 1

What is the extreme f(x)=x^3-2x^2+1x ?
The extreme f(x)=x^3-2x^2+1x is Maximum(1/3 , 4/27),Minimum(1,0)