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Popular >

extreme y=2x^2+8x-1

Solution

extreme points

y = 2 x^{2} + 8 x - 1

Solution

Minimum (- 2, - 9)

Solution steps

f^{'} (x) = 4 x + 8

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

2 x^{2} + 8 x - 1 : - 9

Minimum (- 2, - 9)

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extreme f(x)=x^5-10x^4+2=x^4(x-10)+2 extreme points

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f (x) = x^{9} - x^{7}

Frequently Asked Questions (FAQ)

What is the extreme y=2x^2+8x-1 ?
The extreme y=2x^2+8x-1 is Minimum(-2,-9)