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Popular >

extreme y=(x^3+8)/x

Solution

extreme points

y = \frac{x ^{3} + 8}{x}

Solution

Solution steps

f^{'} (x) = \frac{2 x ^{3} - 8}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

Increasing

Plug

into

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Frequently Asked Questions (FAQ)

What is the extreme y=(x^3+8)/x ?
The extreme y=(x^3+8)/x is Minimum(\sqrt[3]{4},(12)/(\sqrt[3]{4)})