What is the extreme f(x)=(100ln(x+2))/(x+2) ?

The extreme f(x)=(100ln(x+2))/(x+2) is Maximum(e-2,(100)/e)

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extreme f(x)=(100ln(x+2))/(x+2)

extreme points

f (x) = \frac{100 ln ( x + 2 )}{x + 2}

Maximum (e - 2, \frac{100}{e})

Solution steps

f^{'} (x) = \frac{100 ( 1 - ln ( x + 2 ) )}{( x + 2 ) ^{2}}

Find intervals:

Increasing

: - 2 < x < e - 2,

Decreasing

: e - 2 < x < \infty

Plug

x = e - 2

into

\frac{100 ln ( x + 2 )}{x + 2} : \frac{100}{e}

Maximum (e - 2, \frac{100}{e})

3 (e^{- 0.8 t} - e^{- 1.2 t})

f (x) = 6 x^{2} - 8 x + 2

f (x) = ∣ 2 x + 1 ∣

\frac{1}{∣ x ∣ + 1}

f (x, y) = e^{2 x} (x + y^{2} + 2 y) + 10

What is the extreme f(x)=(100ln(x+2))/(x+2) ?
The extreme f(x)=(100ln(x+2))/(x+2) is Maximum(e-2,(100)/e)