What is the extreme f(x)=2x^3+3x^2-36x+17 ?

The extreme f(x)=2x^3+3x^2-36x+17 is Maximum(-3,98),Minimum(2,-27)

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extreme f(x)=2x^3+3x^2-36x+17

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 17

Maximum (- 3, 98), Minimum (2, - 27)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 3

into

2 x^{3} + 3 x^{2} - 36 x + 17 : 98

Maximum (- 3, 98)

Plug

x = 2

into

2 x^{3} + 3 x^{2} - 36 x + 17 : - 27

Minimum (2, - 27)

Maximum (- 3, 98), Minimum (2, - 27)

f (x) = x^{3} + 2 x^{2} - 7 x [0.2]

T (x, y) = 26 - 9 x^{2} - 9 y^{2}

y = 6 x^{2} - 30 x + 9

f (x) = - 15 - 7 x - x^{2}

f (x, y) = - x^{2} + 1 - - y^{2} + 1

What is the extreme f(x)=2x^3+3x^2-36x+17 ?
The extreme f(x)=2x^3+3x^2-36x+17 is Maximum(-3,98),Minimum(2,-27)