What is the extreme (7z+6)/(z-7)+(7z+3)/(z-7) ?

The extreme (7z+6)/(z-7)+(7z+3)/(z-7) is None

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extreme (7z+6)/(z-7)+(7z+3)/(z-7)

extreme points

\frac{7 z + 6}{z - 7} + \frac{7 z + 3}{z - 7}

None

Solution steps

f^{'} (z) = - \frac{107}{( - 7 + z ) ^{2}}

Find intervals:

None

None

f (x) = \frac{( 4 x - 7 )}{x + 3}

\frac{2 x ^{2} - 12 x - 54}{2 x ^{2} + 13 x + 21}

f (x) = 4 x^{3} - 6 x^{2}, - 1 \leq x \leq 1

f (x) = \frac{10 x}{3 x ^{2} + 3}

f (x) = (x - 4)^{2} + (y - 4)^{2} - \frac{4}{5}

What is the extreme (7z+6)/(z-7)+(7z+3)/(z-7) ?
The extreme (7z+6)/(z-7)+(7z+3)/(z-7) is None