What is the extreme f(x)=2x^3-33x^2+144x+3 ?

The extreme f(x)=2x^3-33x^2+144x+3 is Maximum(3,192),Minimum(8,67)

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extreme f(x)=2x^3-33x^2+144x+3

extreme points

f (x) = 2 x^{3} - 33 x^{2} + 144 x + 3

Maximum (3, 192), Minimum (8, 67)

Solution steps

f^{'} (x) = 6 x^{2} - 66 x + 144

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 3

into

2 x^{3} - 33 x^{2} + 144 x + 3 : 192

Maximum (3, 192)

Plug

x = 8

into

2 x^{3} - 33 x^{2} + 144 x + 3 : 67

Minimum (8, 67)

Maximum (3, 192), Minimum (8, 67)

f (x, y) = x^{3} + y^{2} - 4 x y + 17 x - 10 y + 2.021

f (x) = \frac{( 2 x ^{3} + 5 x )}{( x + 7 )}

f (x) = 2 x^{3} - 15 x^{2} + 6

(x - 7) e^{x}

y = 3 - 5 (x + 1)^{2}

What is the extreme f(x)=2x^3-33x^2+144x+3 ?
The extreme f(x)=2x^3-33x^2+144x+3 is Maximum(3,192),Minimum(8,67)