What is the extreme f(x)=6x^2+500x+8000 ?

The extreme f(x)=6x^2+500x+8000 is Minimum(-125/3 ,-7250/3)

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extreme f(x)=6x^2+500x+8000

extreme points

f (x) = 6 x^{2} + 500 x + 8000

Minimum (- \frac{125}{3}, - \frac{7250}{3})

Solution steps

f^{'} (x) = 12 x + 500

Find intervals:

Decreasing

: - \infty < x < - \frac{125}{3},

Increasing

: - \frac{125}{3} < x < \infty

Plug

x = - \frac{125}{3}

into

6 x^{2} + 500 x + 8000 : - \frac{7250}{3}

Minimum (- \frac{125}{3}, - \frac{7250}{3})

f (x, y) = x ln (y) + y e^{x} - x^{2}

f (x, y) = - 2 x - 2 y - x^{2} - y^{2}

f (x) = x y + \frac{1}{x} + \frac{1}{y}

y = 3 x^{2} - 4 x, 0 \leq x \leq 3

f (x) = x^{5} - 5 x - 10

What is the extreme f(x)=6x^2+500x+8000 ?
The extreme f(x)=6x^2+500x+8000 is Minimum(-125/3 ,-7250/3)