What is the extreme f(x)=2x(18-2x^2) ?

The extreme f(x)=2x(18-2x^2) is Minimum(-sqrt(3),-24sqrt(3)),Maximum(sqrt(3),24sqrt(3))

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extreme f(x)=2x(18-2x^2)

extreme points

f (x) = 2 x (18 - 2 x^{2})

Minimum (- 3, - 243), Maximum (3, 243)

Solution steps

f^{'} (x) = 2 (18 - 6 x^{2})

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

2 x (18 - 2 x^{2}) : - 243

Minimum (- 3, - 243)

Plug

x = 3

into

2 x (18 - 2 x^{2}) : 243

Maximum (3, 243)

Minimum (- 3, - 243), Maximum (3, 243)

(x^{2} - 1) \cdot (e^{y} - 1) + (y^{2} - 2 y + 2) e^{y}

f (x) = x x + 6

f (x, y) = x^{2} + y^{2} + 10 x - 4 y

f (x) = 5 x - 4 ln (3 x)

\frac{6}{x + 7}

What is the extreme f(x)=2x(18-2x^2) ?
The extreme f(x)=2x(18-2x^2) is Minimum(-sqrt(3),-24sqrt(3)),Maximum(sqrt(3),24sqrt(3))