en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme ((x^2-9))/(x^2+9)

Solution

extreme points

\frac{( x ^{2} - 9 )}{x ^{2} + 9}

Solution

Minimum (0, - 1)

Solution steps

f^{'} (x) = \frac{36 x}{( x ^{2} + 9 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2} - 9}{x ^{2} + 9} : - 1

Minimum (0, - 1)

Popular Examples

extreme f(x)=x^{1/5}(x^2-9)extreme points

f (x) = x^{\frac{1}{5}} (x^{2} - 9)

extreme f(x)= 2/(x^2-2x-3)extreme points

f (x) = \frac{2}{x ^{2} - 2 x - 3}

extreme f(x)=\sqrt[3]{(5-x)/x}extreme points

extreme (10x^2-18x)/(15x-27)extreme points

\frac{10 x ^{2} - 18 x}{15 x - 27}

extreme f(θ)=2sec(θ)-tan(θ)extreme points

f (θ) = 2 sec (θ) - tan (θ)

Frequently Asked Questions (FAQ)

What is the extreme ((x^2-9))/(x^2+9) ?
The extreme ((x^2-9))/(x^2+9) is Minimum(0,-1)