What is the extreme f(x)=x^2y+xy^2+4xy-5y+3 ?

The extreme f(x)=x^2y+xy^2+4xy-5y+3 is None

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extreme f(x)=x^2y+xy^2+4xy-5y+3

extreme points

f (x) = x^{2} y + x y^{2} + 4 x y - 5 y + 3

None

Solution steps

Find the critical points:

None

x^{2} y + x y^{2} + 4 x y - 5 y + 3

has no critical points, therefore there are no extreme points

None

f (x, y) = 3 x^{2} - 5 y^{2}

f (x) = \frac{4}{( x - 3 ) ^{2}}

f (x) = 11 + 7 x + x^{2}

f (x) = \frac{3 x}{x ^{2} + 7}, 0 \leq x \leq 4

y = x^{2} + 2 x - 1

What is the extreme f(x)=x^2y+xy^2+4xy-5y+3 ?
The extreme f(x)=x^2y+xy^2+4xy-5y+3 is None