What is the extreme f(x)=-x^3+3x-5 ?

The extreme f(x)=-x^3+3x-5 is Minimum(-1,-7),Maximum(1,-3)

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extreme f(x)=-x^3+3x-5

extreme points

f (x) = - x^{3} + 3 x - 5

Minimum (- 1, - 7), Maximum (1, - 3)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 5 : - 7

Minimum (- 1, - 7)

Plug

x = 1

into

- x^{3} + 3 x - 5 : - 3

Maximum (1, - 3)

Minimum (- 1, - 7), Maximum (1, - 3)

f (x) = \frac{2 x + 5}{3}, (0, 5)

f (x) = \frac{( 1 )}{( 3 ) x ^{(3)} - 400 x}

f (x, y) = x^{2} + x y + 2 x + 4 y + 1

f (x) = x^{3} + 3 x^{2} + 2 x

What is the extreme f(x)=-x^3+3x-5 ?
The extreme f(x)=-x^3+3x-5 is Minimum(-1,-7),Maximum(1,-3)