What is the extreme g(x)=xsqrt(18-x) ?

The extreme g(x)=xsqrt(18-x) is Maximum(12,12sqrt(6)),Minimum(18,0)

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extreme g(x)=xsqrt(18-x)

extreme points

g (x) = x 18 - x

Maximum (12, 126), Minimum (18, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 12 )}{2 18 - x}

Find intervals:

Increasing

: - \infty < x < 12,

Decreasing

: 12 < x < 18

Plug

x = 12

into

x 18 - x : 126

Maximum (12, 126)

Plug

x = 18

into

x 18 - x : 0

Minimum (18, 0)

Maximum (12, 126), Minimum (18, 0)

5 x^{2} (x - 11) + 3

f (x) = x^{2} - y^{2} - 14 x + 4 y + 3

y x^{2} + 10 x = 10

f (x) = \frac{5 x}{x ^{2} + 2}

y = \frac{x}{2} - sin (x)

What is the extreme g(x)=xsqrt(18-x) ?
The extreme g(x)=xsqrt(18-x) is Maximum(12,12sqrt(6)),Minimum(18,0)