What is the extreme f(x)=x^2-y^2-14x+4y+3 ?

The extreme f(x)=x^2-y^2-14x+4y+3 is Saddle(7,2)

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extreme f(x)=x^2-y^2-14x+4y+3

extreme points

f (x) = x^{2} - y^{2} - 14 x + 4 y + 3

Saddle (7, 2)

Solution steps

Find the critical points:

(7, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(7, 2) :

Saddle

Saddle (7, 2)

y x^{2} + 10 x = 10

f (x) = \frac{5 x}{x ^{2} + 2}

y = \frac{x}{2} - sin (x)

\frac{x - 5}{x ^{2} - 16 x + 64}

f (x) = 3 x^{\frac{2}{3}} - x, 0 \leq x \leq 27

What is the extreme f(x)=x^2-y^2-14x+4y+3 ?
The extreme f(x)=x^2-y^2-14x+4y+3 is Saddle(7,2)