What is the extreme f(xy)=2x^2+2y^2+4xy-8x+20 ?

The extreme f(xy)=2x^2+2y^2+4xy-8x+20 is None

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extreme f(xy)=2x^2+2y^2+4xy-8x+20

extreme points

f (x y) = 2 x^{2} + 2 y^{2} + 4 x y - 8 x + 20

None

Solution steps

Find the critical points:

None

2 x^{2} + 2 y^{2} + 4 x y - 8 x + 20

has no critical points, therefore there are no extreme points

None

f (x) = ln (3 - ln (x))

f (x) = 12 x^{2} - 2 x^{3}

f (x, y) = x^{2} + y^{2} - 4 y + 4

f (x) = x^{3} - 29 x^{2} - 40 x

f (x) = - 4 x^{2} - 8 x - 1.5

What is the extreme f(xy)=2x^2+2y^2+4xy-8x+20 ?
The extreme f(xy)=2x^2+2y^2+4xy-8x+20 is None