What is the extreme f(x)=x^3-29x^2-40x ?

The extreme f(x)=x^3-29x^2-40x is Maximum(-2/3 , 364/27),Minimum(20,-4400)

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extreme f(x)=x^3-29x^2-40x

extreme points

f (x) = x^{3} - 29 x^{2} - 40 x

Maximum (- \frac{2}{3}, \frac{364}{27}), Minimum (20, - 4400)

Solution steps

f^{'} (x) = 3 x^{2} - 58 x - 40

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 20,

Increasing

: 20 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 29 x^{2} - 40 x : \frac{364}{27}

Maximum (- \frac{2}{3}, \frac{364}{27})

Plug

x = 20

into

x^{3} - 29 x^{2} - 40 x : - 4400

Minimum (20, - 4400)

Maximum (- \frac{2}{3}, \frac{364}{27}), Minimum (20, - 4400)

f (x) = - 4 x^{2} - 8 x - 1.5

f (x, y) = 3 x - 4 x y + 5 y

f (x) = x^{5} + 243

f (x) = 6 - \frac{x ^{3}}{3} + 15 x - x^{2}

f (x) = 3 x^{2} - 12 x + 7, 0 \leq x \leq 4

What is the extreme f(x)=x^3-29x^2-40x ?
The extreme f(x)=x^3-29x^2-40x is Maximum(-2/3 , 364/27),Minimum(20,-4400)