What is the extreme f(x)=4x^3+54x^2+240x ?

The extreme f(x)=4x^3+54x^2+240x is Maximum(-5,-350),Minimum(-4,-352)

Popular >

extreme f(x)=4x^3+54x^2+240x

extreme points

f (x) = 4 x^{3} + 54 x^{2} + 240 x

Maximum (- 5, - 350), Minimum (- 4, - 352)

Solution steps

f^{'} (x) = 12 x^{2} + 108 x + 240

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 5

into

4 x^{3} + 54 x^{2} + 240 x : - 350

Maximum (- 5, - 350)

Plug

x = - 4

into

4 x^{3} + 54 x^{2} + 240 x : - 352

Minimum (- 4, - 352)

Maximum (- 5, - 350), Minimum (- 4, - 352)

f (x) = \frac{3 x}{x ^{2} + 1}, 0 \leq x \leq 3

f (x) = 6 cos (x)

f (x, y) = 4 x^{2} - x y + 4 y^{2}

2 x^{3} + 3 x^{2} - 12 x - 18

f (x) = 4.5 x^{2} - 7.1 x + 3.9

What is the extreme f(x)=4x^3+54x^2+240x ?
The extreme f(x)=4x^3+54x^2+240x is Maximum(-5,-350),Minimum(-4,-352)