What is the extreme 2x^3+3x^2-12x-18 ?

The extreme 2x^3+3x^2-12x-18 is Maximum(-2,2),Minimum(1,-25)

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extreme 2x^3+3x^2-12x-18

extreme points

2 x^{3} + 3 x^{2} - 12 x - 18

Maximum (- 2, 2), Minimum (1, - 25)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 2

into

2 x^{3} + 3 x^{2} - 12 x - 18 : 2

Maximum (- 2, 2)

Plug

x = 1

into

2 x^{3} + 3 x^{2} - 12 x - 18 : - 25

Minimum (1, - 25)

Maximum (- 2, 2), Minimum (1, - 25)

f (x) = 4.5 x^{2} - 7.1 x + 3.9

y = 6 - 2 x^{2} - z^{2}

x^{3} - 9 x^{2} + 24 x - 12

f (x) = (1 - 5 x)^{3} x - 3

9 - x^{2}, - 3 \leq x \leq 2

What is the extreme 2x^3+3x^2-12x-18 ?
The extreme 2x^3+3x^2-12x-18 is Maximum(-2,2),Minimum(1,-25)