What is the extreme y=6-2x^2-z^2 ?

The extreme y=6-2x^2-z^2 is Maximum(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=6-2x^2-z^2

extreme points

y = 6 - 2 x^{2} - z^{2}

Maximum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, z) = 8

Check the sign of at each critical point

Check critical point

(0, 0) :

Maximum

Maximum (0, 0)

x^{3} - 9 x^{2} + 24 x - 12

f (x) = (1 - 5 x)^{3} x - 3

9 - x^{2}, - 3 \leq x \leq 2

f (x) = 1 + \frac{x}{x - 2}

y = \frac{x ^{2} + x - 1}{x - 1}