What is the extreme f(x)=(1-5x)^3sqrt(x-3) ?

The extreme f(x)=(1-5x)^3sqrt(x-3) is Maximum(3,0)

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extreme f(x)=(1-5x)^3sqrt(x-3)

extreme points

f (x) = (1 - 5 x)^{3} x - 3

Maximum (3, 0)

Solution steps

f^{'} (x) = \frac{- 7 ( 5 x - 1 ) ^{2} ( 5 x - 13 )}{2 x - 3}

Find intervals:

Decreasing

: 3 < x < \infty

Plug

x = 3

into

(1 - 5 x)^{3} x - 3 : 0

Maximum (3, 0)

9 - x^{2}, - 3 \leq x \leq 2

f (x) = 1 + \frac{x}{x - 2}

y = \frac{x ^{2} + x - 1}{x - 1}

f (x) = \frac{x ^{6}}{10} - \frac{2 x ^{5}}{3}

f (x, y) = 2 x^{2} + 4 y x - x - 2 y

What is the extreme f(x)=(1-5x)^3sqrt(x-3) ?
The extreme f(x)=(1-5x)^3sqrt(x-3) is Maximum(3,0)