What is the extreme f(x,y)=sqrt(2x^2+4yx-x-2y) ?

The extreme f(x,y)=sqrt(2x^2+4yx-x-2y) is None

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extreme f(x,y)=sqrt(2x^2+4yx-x-2y)

extreme points

f (x, y) = 2 x^{2} + 4 y x - x - 2 y

None

Solution steps

Find the critical points:

None

2 x^{2} + 4 y x - x - 2 y

has no critical points, therefore there are no extreme points

None

f (x) = 2 x + 3

f (x) = cot (x) + 10, - π \leq x \leq \frac{π}{3}

f (x, y) = x^{2} y + 2 x y - 2 x y^{2} + 2

f (x) = x^{4} + 4 x^{3} - 1

f (x, y) = x^{2} + x y + y^{2} - 31 y + 320

What is the extreme f(x,y)=sqrt(2x^2+4yx-x-2y) ?
The extreme f(x,y)=sqrt(2x^2+4yx-x-2y) is None