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Popular >

extreme f(x)=7+2x-2x^2

Solution

extreme points

f (x) = 7 + 2 x - 2 x^{2}

Solution

Maximum (\frac{1}{2}, \frac{15}{2})

Solution steps

f^{'} (x) = - 4 x + 2

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

7 + 2 x - 2 x^{2} : \frac{15}{2}

Maximum (\frac{1}{2}, \frac{15}{2})

Graph

Popular Examples

extreme f(x)=2x^2+x+1,-2<= x<= 3 extreme points

f (x) = 2 x^{2} + x + 1, - 2 \leq x \leq 3

extreme f(x)=(x-3)e^{-x+3-(x-3)^2}extreme points

f (x) = (x - 3) e^{- x + 3 - (x - 3)^{2}}

extreme f(x)=2x^3-3x^2-12x+20 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 20

extreme f(x)=4sqrt(x)-x,2<= x<= 8 extreme points

f (x) = 4 x - x, 2 \leq x \leq 8

extreme f(x)=(x-9)^3(x+5)^2 extreme points

f (x) = (x - 9)^{3} (x + 5)^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=7+2x-2x^2 ?
The extreme f(x)=7+2x-2x^2 is Maximum(1/2 , 15/2)