What is the extreme f(x)=2x^3-3x^2-12x+20 ?

The extreme f(x)=2x^3-3x^2-12x+20 is Maximum(-1,27),Minimum(2,0)

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extreme f(x)=2x^3-3x^2-12x+20

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 20

Maximum (- 1, 27), Minimum (2, 0)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x + 20 : 27

Maximum (- 1, 27)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x + 20 : 0

Minimum (2, 0)

Maximum (- 1, 27), Minimum (2, 0)

f (x) = 4 x - x, 2 \leq x \leq 8

f (x) = (x - 9)^{3} (x + 5)^{2}

f (x) = x^{3} + x^{2} - x + 3

sin (4 x), 0 \leq x \leq \frac{π}{2}

f (x) = \frac{x ^{2} - 4 x + 4}{x - 6}

What is the extreme f(x)=2x^3-3x^2-12x+20 ?
The extreme f(x)=2x^3-3x^2-12x+20 is Maximum(-1,27),Minimum(2,0)