What is the extreme f(x)=-x^3+12x-7 ?

The extreme f(x)=-x^3+12x-7 is Minimum(-2,-23),Maximum(2,9)

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extreme f(x)=-x^3+12x-7

extreme points

f (x) = - x^{3} + 12 x - 7

Minimum (- 2, - 23), Maximum (2, 9)

Solution steps

f^{'} (x) = - 3 x^{2} + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{3} + 12 x - 7 : - 23

Minimum (- 2, - 23)

Plug

x = 2

into

- x^{3} + 12 x - 7 : 9

Maximum (2, 9)

Minimum (- 2, - 23), Maximum (2, 9)

f (x) = x^{2} - 11, - 2 \leq x \leq 4

f (x) = 3 x^{3} - 36 x^{2} + 108 x + 8

f (x, y) = x^{2} - 2 x y + y

f (x) = \frac{x}{2} - sin (x), - π \leq x \leq π

y = x^{2} (x - 3)

What is the extreme f(x)=-x^3+12x-7 ?
The extreme f(x)=-x^3+12x-7 is Minimum(-2,-23),Maximum(2,9)