What is the extreme f(x)=3x^3-36x^2+108x+8 ?

The extreme f(x)=3x^3-36x^2+108x+8 is Maximum(2,104),Minimum(6,8)

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extreme f(x)=3x^3-36x^2+108x+8

extreme points

f (x) = 3 x^{3} - 36 x^{2} + 108 x + 8

Maximum (2, 104), Minimum (6, 8)

Solution steps

f^{'} (x) = 9 x^{2} - 72 x + 108

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 2

into

3 x^{3} - 36 x^{2} + 108 x + 8 : 104

Maximum (2, 104)

Plug

x = 6

into

3 x^{3} - 36 x^{2} + 108 x + 8 : 8

Minimum (6, 8)

Maximum (2, 104), Minimum (6, 8)

f (x, y) = x^{2} - 2 x y + y

f (x) = \frac{x}{2} - sin (x), - π \leq x \leq π

y = x^{2} (x - 3)

f (x) = x (20 - 2 x) (12 - 2 x)

f (x) = 5 x^{2} - 40 ln (x)

What is the extreme f(x)=3x^3-36x^2+108x+8 ?
The extreme f(x)=3x^3-36x^2+108x+8 is Maximum(2,104),Minimum(6,8)