What is the extreme f(x)=5x^2-40ln(x) ?

The extreme f(x)=5x^2-40ln(x) is Minimum(2,20-40ln(2))

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extreme f(x)=5x^2-40ln(x)

extreme points

f (x) = 5 x^{2} - 40 ln (x)

Minimum (2, 20 - 40 ln (2))

Solution steps

f^{'} (x) = 10 x - \frac{40}{x}

Find intervals:

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

5 x^{2} - 40 ln (x) : 20 - 40 ln (2)

Minimum (2, 20 - 40 ln (2))

y = x^{3} - 6 x^{2} + 2

f (x) = x^{3} - 3 x + 9

\frac{x ^{2}}{1 + x}

+ \frac{1}{11 - t}

f (x) = x^{3} - 3 x - 4

What is the extreme f(x)=5x^2-40ln(x) ?
The extreme f(x)=5x^2-40ln(x) is Minimum(2,20-40ln(2))