What is the extreme-0.1t^2+0.8t+98.8,0 = 8 ?

The extreme-0.1t^2+0.8t+98.8,0 = 8 is Maximum(8,98.8)

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extreme-0.1t^2+0.8t+98.8,0<= t>= 8

extreme points

- 0.1 t^{2} + 0.8 t + 98.8, 0 \leq t \geq 8

Maximum (8, 98.8)

Solution steps

Find the critical points:

t = 8

Domain of

- 0.1 t^{2} + 0.8 t + 98.8, 0 \leq t \geq 8 : t \geq 8

Find intervals:

Decreasing

: 8 < t < \infty

Plug the extreme point

x = 8

into

- 0.1 t^{2} + 0.8 t + 98.8 \Rightarrow y = 98.8

Maximum (8, 98.8)

x^{8} ln (x)

f (x) = x^{6} + 4 x^{5} + 10

F (x, y) = 2 x^{5} + x^{3} y^{2} + 6 x y^{4}

f (x) = \frac{9 x}{x ^{2} + 9}

f (x) = - 6 x^{2} + 30 x - 36

What is the extreme-0.1t^2+0.8t+98.8,0<= t>= 8 ?
The extreme-0.1t^2+0.8t+98.8,0<= t>= 8 is Maximum(8,98.8)