What is the extreme f(x)=14x^2-x^3 ?

The extreme f(x)=14x^2-x^3 is Minimum(0,0),Maximum(28/3 , 10976/27)

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extreme f(x)=14x^2-x^3

extreme points

f (x) = 14 x^{2} - x^{3}

Minimum (0, 0), Maximum (\frac{28}{3}, \frac{10976}{27})

Solution steps

f^{'} (x) = 28 x - 3 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{28}{3},

Decreasing

: \frac{28}{3} < x < \infty

Plug

x = 0

into

14 x^{2} - x^{3} : 0

Minimum (0, 0)

Plug

x = \frac{28}{3}

into

14 x^{2} - x^{3} : \frac{10976}{27}

Maximum (\frac{28}{3}, \frac{10976}{27})

Minimum (0, 0), Maximum (\frac{28}{3}, \frac{10976}{27})

f (x) = x^{3} - 3 x^{2} + 6 x - 8

f (x) = \frac{4 ( x - 10 ) ^{2}}{x - 6}, (0, 6)

f (x) = 15 x^{\frac{2}{3}} - x

f (x, y) = x^{2} + 2 x + y^{2} - 2 y + 2

f (x, y) = x^{2} + 2 x y - x y^{2}

What is the extreme f(x)=14x^2-x^3 ?
The extreme f(x)=14x^2-x^3 is Minimum(0,0),Maximum(28/3 , 10976/27)