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Popular >

extreme y=x^3+5

Solution

extreme points

y = x^{3} + 5

Solution

Saddle (0, 5)

Solution steps

f^{'} (x) = 3 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{3} + 5 : 5

Saddle (0, 5)

Graph

Popular Examples

extreme f(x)=x^4+4x^3-9,-4<= x<= 0 extreme points

f (x) = x^{4} + 4 x^{3} - 9, - 4 \leq x \leq 0

extreme f(x)=3x^3+3/2 x^2-2x,-1<= x<= 1 extreme points

f (x) = 3 x^{3} + \frac{3}{2} x^{2} - 2 x, - 1 \leq x \leq 1

extreme 2-(10x)/(x^2+25)extreme points

2 - \frac{10 x}{x ^{2} + 25}

extreme f(x)=7+5x-5x^2 extreme points

f (x) = 7 + 5 x - 5 x^{2}

extreme f(x)=e^{-x}(x^2-1)extreme points

f (x) = e^{- x} (x^{2} - 1)

Frequently Asked Questions (FAQ)

What is the extreme y=x^3+5 ?
The extreme y=x^3+5 is Saddle(0,5)