What is the extreme 2-(10x)/(x^2+25) ?

The extreme 2-(10x)/(x^2+25) is Maximum(-5,3),Minimum(5,1)

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extreme 2-(10x)/(x^2+25)

extreme points

2 - \frac{10 x}{x ^{2} + 25}

Maximum (- 5, 3), Minimum (5, 1)

Solution steps

f^{'} (x) = \frac{10 ( x + 5 ) ( x - 5 )}{( x ^{2} + 25 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

2 - \frac{10 x}{x ^{2} + 25} : 3

Maximum (- 5, 3)

Plug

x = 5

into

2 - \frac{10 x}{x ^{2} + 25} : 1

Minimum (5, 1)

Maximum (- 5, 3), Minimum (5, 1)

f (x) = 7 + 5 x - 5 x^{2}

f (x) = e^{- x} (x^{2} - 1)

h (x) = 2 (x - 5)^{3}

f (x, y) = x^{2} + 2 y^{2} - x y + 3 x + 2 y

f (x) = - 5 x^{3} + 15 x + 6

What is the extreme 2-(10x)/(x^2+25) ?
The extreme 2-(10x)/(x^2+25) is Maximum(-5,3),Minimum(5,1)