en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(x^2+1)e^x

Solution

extreme points

f (x) = (x^{2} + 1) e^{x}

Solution

Saddle (- 1, \frac{2}{e})

Solution steps

f^{'} (x) = e^{x} (x + 1)^{2}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

(x^{2} + 1) e^{x} : \frac{2}{e}

Saddle (- 1, \frac{2}{e})

Graph

Popular Examples

extreme f(x,y)=2xy^3-2x^2y extreme points

f (x, y) = 2 x y^{3} - 2 x^{2} y

extreme f(xy)=e^{-y}(x^2+y^2)extreme points

f (x y) = e^{- y} (x^{2} + y^{2})

extreme f(x)=x(19-37+2x)(37/2-x)extreme points

f (x) = x (19 - 37 + 2 x) (\frac{37}{2} - x)

extreme y=x^2(x^2-5)extreme points

y = x^{2} (x^{2} - 5)

extreme f(x)=6x+18 extreme points

f (x) = 6 x + 18

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2+1)e^x ?
The extreme f(x)=(x^2+1)e^x is Saddle(-1, 2/e)