What is the extreme f(x,y)=2xy^3-2x^2y ?

The extreme f(x,y)=2xy^3-2x^2y is None

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extreme f(x,y)=2xy^3-2x^2y

extreme points

f (x, y) = 2 x y^{3} - 2 x^{2} y

None

Solution steps

Find the critical points:

None

2 x y^{3} - 2 x^{2} y

has no critical points, therefore there are no extreme points

None

f (x y) = e^{- y} (x^{2} + y^{2})

f (x) = x (19 - 37 + 2 x) (\frac{37}{2} - x)

y = x^{2} (x^{2} - 5)

f (x) = 6 x + 18

f (x) = \frac{4 y + 7}{3 - x}