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Popular >

extreme f(x)=x^2+6x+11

Solution

extreme points

f (x) = x^{2} + 6 x + 11

Solution

Minimum (- 3, 2)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x^{2} + 6 x + 11 : 2

Minimum (- 3, 2)

Graph

Popular Examples

extreme f(x)=x^2+6x+17 extreme points

f (x) = x^{2} + 6 x + 17

extreme f(x)=x^2+6x+16 extreme points

f (x) = x^{2} + 6 x + 16

extreme f(x)=4x^3+6x^2 extreme points

f (x) = 4 x^{3} + 6 x^{2}

extreme g(x)=8-5sin(x),0<= x<= pi extreme points

g (x) = 8 - 5 sin (x), 0 \leq x \leq π

extreme y=-(x^3)/((x+2)(x-1))extreme points

y = - \frac{x ^{3}}{( x + 2 ) ( x - 1 )}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+6x+11 ?
The extreme f(x)=x^2+6x+11 is Minimum(-3,2)