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Popular >

extreme f(x)=e^{2x}-4e^x

Solution

extreme points

f (x) = e^{2 x} - 4 e^{x}

Solution

Minimum (ln (2), - 4)

Solution steps

f^{'} (x) = e^{2 x} \cdot 2 - 4 e^{x}

Find intervals:

Decreasing

: - \infty < x < ln (2),

Increasing

: ln (2) < x < \infty

Plug

x = ln (2)

into

e^{2 x} - 4 e^{x} : - 4

Minimum (ln (2), - 4)

Popular Examples

extreme f(x)=4x^3+21x^2+36x-20 extreme points

f (x) = 4 x^{3} + 21 x^{2} + 36 x - 20

extreme (x^2-15)/(x-4)extreme points

\frac{x ^{2} - 15}{x - 4}

extreme f(x)=e^x,0<= x<= ln(18)extreme points

f (x) = e^{x}, 0 \leq x \leq ln (18)

extreme f(x)=2x^3-6x^2-210x+7 extreme points

f (x) = 2 x^{3} - 6 x^{2} - 210 x + 7

extreme f(x)=-3x^5+5x^3+1 extreme points

f (x) = - 3 x^{5} + 5 x^{3} + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=e^{2x}-4e^x ?
The extreme f(x)=e^{2x}-4e^x is Minimum(ln(2),-4)