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Popular >

extreme sqrt(4x+1)

Solution

extreme points

4 x + 1

Solution

Minimum (- \frac{1}{4}, 0)

Solution steps

f^{'} (x) = \frac{2}{4 x + 1}

Find intervals:

Increasing

: - \frac{1}{4} < x < \infty

Plug

x = - \frac{1}{4}

into

4 x + 1 : 0

Minimum (- \frac{1}{4}, 0)

Popular Examples

extreme f(x)=2x^{-3}-x^{-2}extreme points

f (x) = 2 x^{- 3} - x^{- 2}

extreme f(x)=(x^6)/6-ln(x)extreme points

f (x) = \frac{x ^{6}}{6} - ln (x)

extreme f(x)=4x^3-4x^2-4x+6,-1<= x<= 2 extreme points

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 6, - 1 \leq x \leq 2

extreme f(x)=cos(x)-5x,0<= x<= 4pi extreme points

f (x) = cos (x) - 5 x, 0 \leq x \leq 4 π

extreme 4x^3-6x extreme points

4 x^{3} - 6 x

Frequently Asked Questions (FAQ)

What is the extreme sqrt(4x+1) ?
The extreme sqrt(4x+1) is Minimum(-1/4 ,0)