What is the extreme f(x)=x^3+3x^2-9x-3 ?

The extreme f(x)=x^3+3x^2-9x-3 is Maximum(-3,24),Minimum(1,-8)

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extreme f(x)=x^3+3x^2-9x-3

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x - 3

Maximum (- 3, 24), Minimum (1, - 8)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x - 3 : 24

Maximum (- 3, 24)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x - 3 : - 8

Minimum (1, - 8)

Maximum (- 3, 24), Minimum (1, - 8)

f (x) = - x^{3} - 8 x

f (x) = 2 x^{3} - 27 x^{2} + 108 x + 3

f (x) = - 5 x^{2} + 1630 x

y = \frac{5 - x}{2 x + 6}

f (x) = 3 x^{4} - 7 ln (x)

What is the extreme f(x)=x^3+3x^2-9x-3 ?
The extreme f(x)=x^3+3x^2-9x-3 is Maximum(-3,24),Minimum(1,-8)