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Popular >

extreme y=x^2-15x+54

Solution

extreme points

y = x^{2} - 15 x + 54

Solution

Minimum (\frac{15}{2}, - \frac{9}{4})

Solution steps

f^{'} (x) = 2 x - 15

Find intervals:

Decreasing

: - \infty < x < \frac{15}{2},

Increasing

: \frac{15}{2} < x < \infty

Plug

x = \frac{15}{2}

into

x^{2} - 15 x + 54 : - \frac{9}{4}

Minimum (\frac{15}{2}, - \frac{9}{4})

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2-15x+54 ?
The extreme y=x^2-15x+54 is Minimum(15/2 ,-9/4)