What is the extreme f(x)=x^5-5x+6 ?

The extreme f(x)=x^5-5x+6 is Maximum(-1,10),Minimum(1,2)

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extreme f(x)=x^5-5x+6

extreme points

f (x) = x^{5} - 5 x + 6

Maximum (- 1, 10), Minimum (1, 2)

Solution steps

f^{'} (x) = 5 x^{4} - 5

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{5} - 5 x + 6 : 10

Maximum (- 1, 10)

Plug

x = 1

into

x^{5} - 5 x + 6 : 2

Minimum (1, 2)

Maximum (- 1, 10), Minimum (1, 2)

f (x) = 2 x^{2} + 3 x y + 4 y^{2} + 2 x - 10 y

f (x) = x^{2} + 4 x + 9

f (x) = - x^{2} - y^{2} + 2 x + 4 y - 5

f (x) = (1 - x)^{2} (5 + x)

What is the extreme f(x)=x^5-5x+6 ?
The extreme f(x)=x^5-5x+6 is Maximum(-1,10),Minimum(1,2)