What is the extreme f(x)=(1-x)^2(5+x) ?

The extreme f(x)=(1-x)^2(5+x) is Maximum(-3,32),Minimum(1,0)

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extreme f(x)=(1-x)^2(5+x)

extreme points

f (x) = (1 - x)^{2} (5 + x)

Maximum (- 3, 32), Minimum (1, 0)

Solution steps

f^{'} (x) = 3 (x - 1) (x + 3)

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

(1 - x)^{2} (5 + x) : 32

Maximum (- 3, 32)

Plug

x = 1

into

(1 - x)^{2} (5 + x) : 0

Minimum (1, 0)

Maximum (- 3, 32), Minimum (1, 0)

f (x, y) = ln (x y) + 2 x^{2} - x y - 6 x

y = (x - 4)^{2} - 8

f (x) = x + e^{- 3 x}

y = (6 x - 5) e^{6 - 2 x}

f (x, y) = 1 - x^{2} + 1 - y^{2}

What is the extreme f(x)=(1-x)^2(5+x) ?
The extreme f(x)=(1-x)^2(5+x) is Maximum(-3,32),Minimum(1,0)