What is the extreme y=(6x-5)e^{6-2x} ?

The extreme y=(6x-5)e^{6-2x} is Maximum(4/3 ,3e^{10/3})

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extreme y=(6x-5)e^{6-2x}

extreme points

y = (6 x - 5) e^{6 - 2 x}

Maximum (\frac{4}{3}, 3 e^{\frac{10}{3}})

Solution steps

f^{'} (x) = - 4 e^{- 2 (- 3 + x)} (3 x - 4)

Find intervals:

Increasing

: - \infty < x < \frac{4}{3},

Decreasing

: \frac{4}{3} < x < \infty

Plug

x = \frac{4}{3}

into

(6 x - 5) e^{6 - 2 x} : 3 e^{\frac{10}{3}}

Maximum (\frac{4}{3}, 3 e^{\frac{10}{3}})

f (x, y) = 1 - x^{2} + 1 - y^{2}

- x e^{- \frac{x}{4}}

f (x) = x^{2} - 2 x, 1 \leq x \leq 3

f (x) = x^{2} - 2 x, 1 \leq x \leq 4

f (x) = \frac{7 x}{x - 4}

What is the extreme y=(6x-5)e^{6-2x} ?
The extreme y=(6x-5)e^{6-2x} is Maximum(4/3 ,3e^{10/3})