What is the extreme f(x)=8x+11x^{8/11} ?

The extreme f(x)=8x+11x^{8/11} is Minimum(-1,3),Maximum(0,0)

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extreme f(x)=8x+11x^{8/11}

extreme points

f (x) = 8 x + 11 x^{\frac{8}{11}}

Minimum (- 1, 3), Maximum (0, 0)

Solution steps

f^{'} (x) = 8 + \frac{8}{x ^{\frac{3}{11}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

8 x + 11 x^{\frac{8}{11}} : 3

Minimum (- 1, 3)

Plug

x = 0

into

8 x + 11 x^{\frac{8}{11}} : 0

Maximum (0, 0)

Minimum (- 1, 3), Maximum (0, 0)

f (x, y) = x - 2 y g (x, y) = x^{2} + y^{2} = 25

f (x) = x^{3} + x^{2} y - y^{2} - 4 y

y = x^{\frac{4}{5}} (x - 1)

f (x) = \frac{( x ^{2} - 11 )}{x + 6}

\frac{64}{x ^{2} + 6 x - 7}

What is the extreme f(x)=8x+11x^{8/11} ?
The extreme f(x)=8x+11x^{8/11} is Minimum(-1,3),Maximum(0,0)