What is the extreme 0.05x+20+(125)/x ?

The extreme 0.05x+20+(125)/x is Maximum(-50,15),Minimum(50,25)

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extreme 0.05x+20+(125)/x

extreme points

0.05 x + 20 + \frac{125}{x}

Maximum (- 50, 15), Minimum (50, 25)

Solution steps

Find the critical points:

x = - 50, x = 50

Domain of

0.05 x + 20 + \frac{125}{x} : x < 0 or x > 0

Find intervals:

Increasing

: - \infty < x < - 50,

Decreasing

: - 50 < x < 0,

Decreasing

: 0 < x < 50,

Increasing

: 50 < x < \infty

Plug the extreme point

x = - 50

into

0.05 x + 20 + \frac{125}{x} \Rightarrow y = 15

Maximum (- 50, 15)

Plug the extreme point

x = 50

into

0.05 x + 20 + \frac{125}{x} \Rightarrow y = 25

Minimum (50, 25)

Maximum (- 50, 15), Minimum (50, 25)

f (x) = \frac{9 ( t - 2 ) ^{2}}{t ^{2}}

x y - 5 x - 5 y - x^{2} - y^{2}

e^{2 x}

f (x, y) = 2 x^{2} + 3 y^{2} - 4 x - 12 y + 13

f (x) = - 4 x^{4} + 3 x^{2} - 15 x + 5

What is the extreme 0.05x+20+(125)/x ?
The extreme 0.05x+20+(125)/x is Maximum(-50,15),Minimum(50,25)