What is the extreme f(x,y)=xy-4y-16x+64 ?

The extreme f(x,y)=xy-4y-16x+64 is Saddle(4,16)

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extreme f(x,y)=xy-4y-16x+64

extreme points

f (x, y) = x y - 4 y - 16 x + 64

Saddle (4, 16)

Solution steps

Find the critical points:

(4, 16)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(4, 16) :

Saddle

Saddle (4, 16)

y = cos (x)

2 x^{2} + 24 x - 6

f (x, y) = ((\frac{( 1 - x )}{x}) y)

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 6

f (x) = x^{\frac{4}{3}}, - 1 \leq x \leq 8

What is the extreme f(x,y)=xy-4y-16x+64 ?
The extreme f(x,y)=xy-4y-16x+64 is Saddle(4,16)