What is the extreme f(x)=(In(x^2-1))/(x^2-1) ?

The extreme f(x)=(In(x^2-1))/(x^2-1) is None

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extreme f(x)=(In(x^2-1))/(x^2-1)

extreme points

f (x) = \frac{I n ( x ^{2} - 1 )}{x ^{2} - 1}

None

Solution steps

Find the critical points:

None

\frac{I n ( x ^{2} - 1 )}{x ^{2} - 1}

has no critical points, therefore there are no extreme points

None

16 (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}})

f (x, y) = x^{2} + x y + y^{2} - 22 y + 161

f (x) = 3 x^{6} - 7 x^{5}

f (x, y) = e^{x^{2} + 3 y^{2} + 15}

g (x) = x^{3} - 2 x^{2} - 4 x + 8

What is the extreme f(x)=(In(x^2-1))/(x^2-1) ?
The extreme f(x)=(In(x^2-1))/(x^2-1) is None